17(x)=24x^2

Solution for 17(x)=24x^2 equation:

17(x)=24x^2

We move all terms to the left:

17(x)-(24x^2)=0

determiningTheFunctionDomain
-24x^2+17x=0

a = -24; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-24)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-24}=\frac{-34}{-48}
=17/24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-24}=\frac{0}{-48}
=0
$